Answer 6.5
The ShannonHartley theorem (see section 2.4) can be
written as:
C/B = log2[1 + Eb.C/N0.B]
Now for Eb/N0 equal to -1.2 dB, the
ratio Eb/N0 = 10-1.2/10 = 0.76.
The bandwidth efficiency C/B that can be supported
is thus:
C/B = log2[1 + 0.76C/B]
therefore:
C/B = 0.3 bits/second/Hz (approximately).