Answer 2.12
The ShannonHartley theorem can be written as:
C/B = log2[1 + Eb.C/N0.B]
Now for Eb/N0 = 0.6 dB,
the ratio Eb/N0 = 100.6/10
= 0.871.
The bandwidth efficiency C/B that can be supported is thus:
C/B = log2[1 + 0.871C/B]
therefore:
C/B = 0.6 bits/second/Hz (approximately).
In a bandwidth of 3400 Hz, the system can thus
operate at an information transfer rate of 3400 x 0.6 = 2040 bps.